Converting password/string to Phonetic Alphabet [Python]

So, every time my buddies stop by, ask, what's the WIFI's password? then I usually give them a piece of paper with a 160 Bit password of 20 Characters like:

{[Ck~Yv~xV9~-R9EMi-k so they go like: can you read this back to me?

So as I've been doing some code, I wanted to be lazy and get my generated passwords in the phonetic alphabet in order to make it easy to pass on:

and this is the result:

#!/usr/bin/python

import sys




if len(sys.argv) < 2:

print "[-] Nothing to do, please provide the password or string: python script.py myPa$$w0rd""

sys.exit()




d = {"a":"alpha","b":"bravo","c":"charlie","d":"delta","e":"echo","f":"foxtrot","g":"golf","h":"hotel","i":"india","j":"juliett","k":"kilo","l":"lima","m":"mike","n":"november","o":"oscar","p":"papa","q":"quebec","r":"romeo","s":"sierra","t":"tango","u":"uniform","v":"victor","w":"whiskey","x":"x-ray","y":"yankee","z":"zulu","-":"dash","0":"Zero", "1":"One", "2":"Two", "3":"Three", "4":"Four", "5":"Five", "6":"Six", "7":"Seven", "8":"Eight", "9":"Nine"}




print("[*] Your password/string of lenght:%d can be read as follows:\n" % (len(sys.argv[1])))

for char in sys.argv[1]:

if char.lower() in d:

if char.lower() == char:

print d[char]

else:

print d[char.lower()].upper()

else:

print char




----

output example:




$ python passToWords.py {[Ck~Yv~xV9~-R9EMi-k

[*] Your password/string of lenght:20 can be read as follows:

{

[

CHARLIE

kilo

~

YANKEE

victor

~

x-ray

VICTOR

Nine

~

dash

ROMEO

Nine

ECHO

MIKE

india

dash

kilo